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2x^2=9.8
We move all terms to the left:
2x^2-(9.8)=0
We add all the numbers together, and all the variables
2x^2-9.8=0
a = 2; b = 0; c = -9.8;
Δ = b2-4ac
Δ = 02-4·2·(-9.8)
Δ = 78.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{78.4}}{2*2}=\frac{0-\sqrt{78.4}}{4} =-\frac{\sqrt{}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{78.4}}{2*2}=\frac{0+\sqrt{78.4}}{4} =\frac{\sqrt{}}{4} $
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